// Informatik 2011 - Lindenmayer-Challenge
// Program: MiltenbergerKlausUlrich1.cpp
// Author: Klaus-Ulrich Miltenberger
#include
#include
// PRE : unsigned integer value n represents the number of iterations
// POST : draws the word w_(i^F)
void f (char sword, char* production, const int i)
{
if (i == 0)
// draw sword
{
if (sword == 'F')
ifm::forward(); // F
if (sword == '+')
ifm::left(60);
if (sword == '-')
ifm::right(60);
}
else
{
for (int j = 0; j < 10; ++j)
{
if (*(production+j) == sword)
f(sword, production, i-1);
else
// draw(*production+j)
{
if (*(production+j) == 'F')
ifm::forward(); // F
if (*(production+j) == '+')
ifm::left(60);
if (*(production+j) == '-')
ifm::right(60);
}
}
}
}
int main()
{
char sword = 'F';
char production [] = "+FFF-FFF+F";
int n;
std::cout << "\n Number of iterations : n = ";
// n = 9 suggested... (could take a minute to draw!)
std::cin >> n;
f(sword, production, n);
return 0;
}
